ساخت دیکشنری

Question

ساخت دیکشنری

سوال

برنامه ای بنویسید که دو لیست زیر را تبدیل به دیکشنری کند.

keys = [“one”, “six”, “five”, “ten”, “nine”, “three”, “four”, “eight”, “two”, “seven”]

values = [6, 7, 1, 2, 9, 4, 10, 3, 8, 5]

نکته:

عناصر هر دو لیست باید به صورت مرتب شده تبدیل به یک دیکشنری شوند.

حل شده 0

انجمن برنامه نویسان پایتون Ahmad Mirzaei 6 ماه 5 پاسخ ها 117 دیده شده 1

درباره Ahmad Mirzaei

پاسخ ها ( ۵ )

mostafaghasemi

4

۱۴۰۲-۰۹-۰۳ در ۲۰:۲۲

پاسخ دادن

keys = ["one", "six", "five", "ten", "nine", "three", "four", "eight", "two", "seven"]

values = [6, 7, 1, 2, 9, 4, 10, 3, 8, 5]

sorted_Keys = sorted(keys)
sorted_Valuse = sorted(values)

dict_Number= dict(zip(sorted_Keys, sorted_Valuse))
print(dict_Number)

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keys = ["one", "six", "five", "ten", "nine", "three", "four", "eight", "two", "seven"]

values = [6, 7, 1, 2, 9, 4, 10, 3, 8, 5]

sorted_Keys = sorted(keys)

sorted_Valuse = sorted(values)

dict_Number= dict(zip(sorted_Keys, sorted_Valuse))

print(dict_Number)

Maryam Zebarjad
3
۱۴۰۲-۰۹-۰۷ در ۱۰:۳۷

پاسخ دادن
سلام

باید دیکشنری که ساخته میشه هر عدد معادل حروفی خودش باشد مثلا one:1 two:2

Ahmad Mirzaei

3

۱۴۰۲-۰۹-۰۴ در ۱۹:۱۹

پاسخ دادن

"""
The code creates a dictionary where numbers are converted to their word representations.
The numbers are sorted in ascending order and then converted to words using the "n2w" library.
The final dictionary is printed out.
"""
from n2w import convert
key = ["one", "six", "five", "ten", "nine", "three", "four", "eight", "two", "seven"]
value = [6, 7, 1, 2, 9, 4, 10, 3, 8, 5]
numDict = {}
for i in value:
    numDict[i] = convert(i)
print(sorted(numDict.items()))

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"""

The code creates a dictionary where numbers are converted to their word representations.

The numbers are sorted in ascending order and then converted to words using the "n2w" library.

The final dictionary is printed out.

"""

from n2w import convert

key = ["one", "six", "five", "ten", "nine", "three", "four", "eight", "two", "seven"]

value = [6, 7, 1, 2, 9, 4, 10, 3, 8, 5]

numDict = {}

for i in value:

numDict[i] = convert(i)

print(sorted(numDict.items()))

زرین
2
۱۴۰۲-۰۹-۰۵ در ۱۸:۲۶

پاسخ دادن
keys = sorted(keys)
values = sorted(values)
A = dict(zip(keys,values));A

ارسال یک پاسخ

سوال قبلی

سوال بعدی

Maryam Zebarjad · Accepted Answer · ۱۴۰۲-۰۹-۰۴

import enum  
import operator 
keys=sorted(["one","six","five","ten","nine","three","four","eight","two","seven"])
values=sorted([6, 7, 1, 2, 9, 4, 10, 3, 8, 5])     
class digits(enum.Enum):            
    one=1
    two=2
    three=3
    four=4
    five=5
    six=6
    seven=7
    eight=8
    nine=9
    ten=10
dic1={key:digits[key].value for key in keys}
print(dict(sorted(dic1.items(),key=operator.itemgetter(1))))

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import enum

import operator

keys=sorted(["one","six","five","ten","nine","three","four","eight","two","seven"])

values=sorted([6, 7, 1, 2, 9, 4, 10, 3, 8, 5])

class digits(enum.Enum):

one=1

two=2

three=3

four=4

five=5

six=6

seven=7

eight=8

nine=9

ten=10

dic1={key:digits[key].value for key in keys}

print(dict(sorted(dic1.items(),key=operator.itemgetter(1))))