مقایسه لیست خرید (تمرین پایتون پیشرفته – درسمن)

Question

مقایسه لیست خرید (تمرین پایتون پیشرفته – درسمن)

سوال

برنامه ای بنویسید که لیست خرید دو مشتری را که تعداد اقلام آنها برابر می باشد را با هم مقایسه کرده و تعداد اقلام نظیر به نظیر مشابه هم را بدست آورده و چاپ کند.

مثلا : برای دو لیست زیر نتیجه ۳ می شود

[“Milk” ,” Cheese” ,” Butter” ,” Tomato”,” Banana”,”Apple” ]

[“Orange” ,” Cheese” ,” Kiwi” ,” Tomato”,” Banana”,” Butter” ]

در حال بررسی 0

انجمن برنامه نویسان پایتون مهدی عباسی 3 سال 13 پاسخ ها 536 دیده شده 0

درباره مهدی عباسی

پاسخ ها ( ۱۳ )

ارسال یک پاسخ

سوال قبلی

سوال بعدی

maryam.zbr · Answer 1 · ۱۴۰۲-۰۵-۲۴

sabad1=[]
sabad2=[]
flag=0
count=int(input('How many item do you have in your list:'))
for i in range(count):
    sabad1.append(str(input('Enter your items of basket1:')))
print(sabad1)    
for i in range(count):
    sabad2.append(str(input('Enter your items of basket2:')))
print(sabad2)
for i in range(0,len(sabad1)):
    if sabad1[i].lower()==sabad2[i].lower():
        flag+=1    
print(flag)

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sabad1=[]

sabad2=[]

flag=0

count=int(input('How many item do you have in your list:'))

for i in range(count):

sabad1.append(str(input('Enter your items of basket1:')))

print(sabad1)

for i in range(count):

sabad2.append(str(input('Enter your items of basket2:')))

print(sabad2)

for i in range(0,len(sabad1)):

if sabad1[i].lower()==sabad2[i].lower():

flag+=1

print(flag)

Hirad · Answer 2 · ۱۴۰۰-۰۶-۳۰

import operator  

# Exception Handling & Checking the Equal Items ------------------------------- 
def  listsChecking(list1,list2):
    if len(list1)!=len(list2):
        raise RuntimeError ("The purchase items are not equal")
    count = 0
    for item in range(len(list1)):
        if operator.eq(list1[item],list2[item]):
            count+=1
    return count 

# Sample Customer Lists -------------------------------------------------------

customerList1 = ["Milk" ,"Cheese" ,"Butter" ,"Tomato","Banana","Apple"]
customerList2 = ["Orange" ,"Cheese" ,"Kiwi" ,"Tomato","Banana","Butter"] 

# Main Code -------------------------------------------------------------------

try:
    counter=listsChecking(customerList1,customerList2)
    print(f"The quantity of equal items is: {counter}")
except RuntimeError as error:
    print(error)

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import operator

# Exception Handling & Checking the Equal Items -------------------------------

def listsChecking(list1,list2):

if len(list1)!=len(list2):

raise RuntimeError ("The purchase items are not equal")

count = 0

for item in range(len(list1)):

if operator.eq(list1[item],list2[item]):

count+=1

return count

# Sample Customer Lists -------------------------------------------------------

customerList1 = ["Milk" ,"Cheese" ,"Butter" ,"Tomato","Banana","Apple"]

customerList2 = ["Orange" ,"Cheese" ,"Kiwi" ,"Tomato","Banana","Butter"]

# Main Code -------------------------------------------------------------------

try:

counter=listsChecking(customerList1,customerList2)

print(f"The quantity of equal items is: {counter}")

except RuntimeError as error:

print(error)

M.jahangiri · Answer 3 · ۱۴۰۰-۰۶-۲۸

# Exception class---------------------------
class myException(Exception):
    def __init__(self, message) :
        super().__init__(message)
        self.message=message
    def __str__(self) :
        return f"Erorr is: {self.message}........"    
# Exception cheker fun---------------------------
def lenChek(list1,list2):
    if len(list1)!=len(list2) :
        raise myException(" invoice items not equle")
# ---------------- main pro -------------------------
costomer1=["Orange" , "Cheese" , "Kiwi" , "Tomato", "Banana","Butter"]
costomer2=["Milk" , "Cheese" , "Butter" , "Tomato", "Banana","Apple" ]
# if you want test myException run this ann comment above syntaxes-------
# costomer1=[input("Added items to invoice: ") in range(int(input("Enter the number of invoice items")))]
# costomer2=[input("Added items to invoice: ") in range(int(input("Enter the number of invoice items")))]
def isequl(x,y):
    if x==y:
        return True
try:
    counter=0
    lenChek(costomer1,costomer2)
    for i in range(len(costomer1)):
        value=isequl(costomer1[i],costomer2[i])
        if value==True:
            counter+=1
    print(counter)       
except myException as erorr:
    print(erorr)

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# Exception class---------------------------

class myException(Exception):

def __init__(self, message) :

super().__init__(message)

self.message=message

def __str__(self) :

return f"Erorr is: {self.message}........"

# Exception cheker fun---------------------------

def lenChek(list1,list2):

if len(list1)!=len(list2) :

raise myException(" invoice items not equle")

# ---------------- main pro -------------------------

costomer1=["Orange" , "Cheese" , "Kiwi" , "Tomato", "Banana","Butter"]

costomer2=["Milk" , "Cheese" , "Butter" , "Tomato", "Banana","Apple" ]

# if you want test myException run this ann comment above syntaxes-------

# costomer1=[input("Added items to invoice: ") in range(int(input("Enter the number of invoice items")))]

# costomer2=[input("Added items to invoice: ") in range(int(input("Enter the number of invoice items")))]

def isequl(x,y):

if x==y:

return True

try:

counter=0

lenChek(costomer1,costomer2)

for i in range(len(costomer1)):

value=isequl(costomer1[i],costomer2[i])

if value==True:

counter+=1

print(counter)

except myException as erorr:

print(erorr)

Mona Azizi Jalilian · Answer 4 · ۱۴۰۰-۰۶-۲۷

import operator
# ----------------------------------------------------------------------
### tow sample lists
shoppingList1 = ["Milk" ,"Cheese" ,"Butter" ,"Tomato","Banana","Apple"]
shoppingList2 = ["Orange" ,"Cheese" ,"Kiwi" ,"Tomato","Banana","Butter"]

### number of same items in two shopping lists
def numberOfSameItems(list1,list2):
    counter = 0
    for i in range(len(list1)):
        if operator.eq(list1[i],list2[i]):
            counter+=1
    return counter
# ----------------------------------------------------------------------   
print(numberOfSameItems(shoppingList1,shoppingList2))

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import operator

# ----------------------------------------------------------------------

### tow sample lists

shoppingList1 = ["Milk" ,"Cheese" ,"Butter" ,"Tomato","Banana","Apple"]

shoppingList2 = ["Orange" ,"Cheese" ,"Kiwi" ,"Tomato","Banana","Butter"]

### number of same items in two shopping lists

def numberOfSameItems(list1,list2):

counter = 0

for i in range(len(list1)):

if operator.eq(list1[i],list2[i]):

counter+=1

return counter

# ----------------------------------------------------------------------

print(numberOfSameItems(shoppingList1,shoppingList2))

Ahmad Mirzaei · Answer 5 · ۱۴۰۲-۰۹-۰۳

list1 = ["Milk", "Cheese", "Butter", "Tomato","Banana", "Apple"]

list2 = ["Orange", "Cheese", "Kiwi", "Tomato",  "Banana", "Butter"]

mapList = (list(map(lambda x, y: x if x == y else None, list1, list2)))
for item in mapList:
    if item:
        print(item)

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list1 = ["Milk", "Cheese", "Butter", "Tomato","Banana", "Apple"]

list2 = ["Orange", "Cheese", "Kiwi", "Tomato", "Banana", "Butter"]

mapList = (list(map(lambda x, y: x if x == y else None, list1, list2)))

for item in mapList:

if item:

print(item)

Ellnamin · Answer 6 · ۱۴۰۰-۱۲-۱۹

class shoppingList:
    def __init__(self,boughtItems):
        self.boughtItems=boughtItems
    ################################
    def __str__(self):
        return f'{self.boughtItems}'
    ################################
    def compareLists(self,shoppingList):
        if len(self.boughtItems)==len(shoppingList.boughtItems):
            count=0
            for i in range (len(self.boughtItems)):
                if self.boughtItems[i].lower().strip()==shoppingList.boughtItems[i].lower().strip():
                    count+=1
        return count
#=================================================

list1=['Milk', 'Watermelon', 'Banana', 'Blueberry', 'Paper', 'chicken' ]
list2=['milk', 'pen' ,'BananA' ,'BlueBerry', 'toy', 'cloth' ]

shoppingList1=shoppingList(list1)
shoppingList2=shoppingList(list2)

countOfCorrespondingItems=shoppingList1.compareLists(shoppingList2)
print (countOfCorrespondingItems)

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class shoppingList:

def __init__(self,boughtItems):

self.boughtItems=boughtItems

################################

def __str__(self):

return f'{self.boughtItems}'

################################

def compareLists(self,shoppingList):

if len(self.boughtItems)==len(shoppingList.boughtItems):

count=0

for i in range (len(self.boughtItems)):

if self.boughtItems[i].lower().strip()==shoppingList.boughtItems[i].lower().strip():

count+=1

return count

#=================================================

list1=['Milk', 'Watermelon', 'Banana', 'Blueberry', 'Paper', 'chicken' ]

list2=['milk', 'pen' ,'BananA' ,'BlueBerry', 'toy', 'cloth' ]

shoppingList1=shoppingList(list1)

shoppingList2=shoppingList(list2)

countOfCorrespondingItems=shoppingList1.compareLists(shoppingList2)

print (countOfCorrespondingItems)

Reza · Answer 7 · ۱۴۰۰-۰۶-۲۸

import json


# Consider that there is a json file called 'customers_purchase'
# next to the main program file from which the information is fetched.
# The information stored in the file is as follows:
# [{"customer1":[....]}, {"customer2":[....]}, ....]


with open("customers_purchase.json", "r") as customers_purchase:
    customers_purchase = json.load(customers_purchase)


counter = 0
customers_purchase_comparession_list = list()
while counter != len(customers_purchase) - 1:
    for index in range(counter + 1, len(customers_purchase)):
            for key, value in customers_purchase[counter].items():
                customer_name1 = key
                customer_purchase1 = value

            for key, value in customers_purchase[index].items():
                customer_name2 = key
                customer_purchase2 = value
            
            c = 0
            for i in range(len(customer_purchase1)):
                if customer_purchase1[i] == customer_purchase2[i]:
                    c += 1
            customers_purchase_comparession_list.append((customer_name1, customer_name2, c))    

    counter += 1

print(customers_purchase_comparession_list)

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import json

# Consider that there is a json file called 'customers_purchase'

# next to the main program file from which the information is fetched.

# The information stored in the file is as follows:

# [{"customer1":[....]}, {"customer2":[....]}, ....]

with open("customers_purchase.json", "r") as customers_purchase:

customers_purchase = json.load(customers_purchase)

counter = 0

customers_purchase_comparession_list = list()

while counter != len(customers_purchase) - 1:

for index in range(counter + 1, len(customers_purchase)):

for key, value in customers_purchase[counter].items():

customer_name1 = key

customer_purchase1 = value

for key, value in customers_purchase[index].items():

customer_name2 = key

customer_purchase2 = value

c = 0

for i in range(len(customer_purchase1)):

if customer_purchase1[i] == customer_purchase2[i]:

c += 1

customers_purchase_comparession_list.append((customer_name1, customer_name2, c))

counter += 1

print(customers_purchase_comparession_list)

ijavadddd · Answer 8 · ۱۴۰۰-۰۶-۲۶

customer1=["Milk" ," Cheese" ," Butter" ," Tomato"," Banana","Apple" ]
customer2=["Orange" ," Cheese" ," Kiwi" ," Tomato"," Banana"," Butter" ]

count=0
for i in range(0,len(customer1)):
    if customer1[i]==customer2[i]:
        count+=1
print(count)

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customer1=["Milk" ," Cheese" ," Butter" ," Tomato"," Banana","Apple" ]

customer2=["Orange" ," Cheese" ," Kiwi" ," Tomato"," Banana"," Butter" ]

count=0

for i in range(0,len(customer1)):

if customer1[i]==customer2[i]:

count+=1

print(count)

mohsen karimi · Answer 9 · ۱۴۰۰-۰۶-۲۶

"""answer for similarity of lists"""

list1 = ["Milk"," Cheese" ," Butter" ," Tomato"," Banana","Apple"]
list2 = ["Orange" ," Cheese" ," Kiwi" ," Tomato"," Banana"," Butter"]
dict1 = dict(enumerate(list1))
dict2 = dict(enumerate(list2))
list3 = []
for key,value in dict1.items():
    for k , v in dict2.items():
        if key == k and value ==v:
            list3.append(value)

print(f"{list3} -> {len(list3)}  ")

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"""answer for similarity of lists"""

list1 = ["Milk"," Cheese" ," Butter" ," Tomato"," Banana","Apple"]

list2 = ["Orange" ," Cheese" ," Kiwi" ," Tomato"," Banana"," Butter"]

dict1 = dict(enumerate(list1))

dict2 = dict(enumerate(list2))

list3 = []

for key,value in dict1.items():

for k , v in dict2.items():

if key == k and value ==v:

list3.append(value)

print(f"{list3} -> {len(list3)} ")

Dorsa soleymani · Answer 10 · ۱۴۰۰-۰۶-۲۶

from operator import eq
list1=["Mike","cheese","Butter","Tomato","Banana","Apple"]
list2= ["orange","cheese","kiwi","Tomato","Banana","Butter"]
 
print(len([i for i in list(map(eq, list1,list2)) if i==True]))

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from operator import eq

list1=["Mike","cheese","Butter","Tomato","Banana","Apple"]

list2= ["orange","cheese","kiwi","Tomato","Banana","Butter"]

print(len([i for i in list(map(eq, list1,list2)) if i==True]))

MohammadJavad · Answer 11 · ۱۴۰۰-۰۶-۲۵

# Test Example customer 1 : Milk,Cheese,Butter,Tomato,Banana,Apple
# Test Example customer 2 : Orange,Cheese,Kiwi,Tomato,Banana,Butter
# Test Answer : 4
class ErrorMessage(Exception):
    pass

def comparison(user1,user2):
    listOfCommonItems=list(filter(lambda item : item in user2,user1))
    count=len(listOfCommonItems)
    print(f"ُ\n The Number of Common Items in Two Customer is : {count} ")
    
    
try: 
    item1=input("Please Enter Your items :")
    listuser1=item1.split(",")
    
    for i in listuser1:
        if i.isnumeric():
            raise ErrorMessage("ERROR!!! Please Enter Items as String. ")

    item2=input("Please Enter Your items :")
    listuser2=item2.split(",")

    for j in listuser2:
        if j.isnumeric():
            raise ErrorMessage("ERROR!!! Please Enter Items as String. ")

    print(f"\n List Of Items Customer 1 is : {listuser1}")
    print(f"\n List Of Items Customer 2 is : {listuser2}")

    comparison(listuser1,listuser2)

except ErrorMessage as error :
        print(error)

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# Test Example customer 1 : Milk,Cheese,Butter,Tomato,Banana,Apple

# Test Example customer 2 : Orange,Cheese,Kiwi,Tomato,Banana,Butter

# Test Answer : 4

class ErrorMessage(Exception):

pass

def comparison(user1,user2):

listOfCommonItems=list(filter(lambda item : item in user2,user1))

count=len(listOfCommonItems)

print(f"ُ\n The Number of Common Items in Two Customer is : {count} ")

try:

item1=input("Please Enter Your items :")

listuser1=item1.split(",")

for i in listuser1:

if i.isnumeric():

raise ErrorMessage("ERROR!!! Please Enter Items as String. ")

item2=input("Please Enter Your items :")

listuser2=item2.split(",")

for j in listuser2:

if j.isnumeric():

raise ErrorMessage("ERROR!!! Please Enter Items as String. ")

print(f"\n List Of Items Customer 1 is : {listuser1}")

print(f"\n List Of Items Customer 2 is : {listuser2}")

comparison(listuser1,listuser2)

except ErrorMessage as error :

print(error)

jahan · Answer 12 · ۱۴۰۰-۰۶-۲۵

1

list1=['Milk','Cheese','Butter','Tomato','Banana','Apple']

list2=['Orange','Cheese','Kiwi','Tomato','Banana','Butter']
list4=[]
list5=[]
list3=(filter(lambda x:x in list2 ,list1))
for n in list3:
    list4.append(n)

print(list4)
print(len(list4))

for i in list1:
    for j in range(len(list2)):
        if i!=list2[j]:
                continue
        list5.append(i)
print(list5)
print(len(list5))

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list1=['Milk','Cheese','Butter','Tomato','Banana','Apple']

list2=['Orange','Cheese','Kiwi','Tomato','Banana','Butter']

list4=[]

list5=[]

list3=(filter(lambda x:x in list2 ,list1))

for n in list3:

list4.append(n)

print(list4)

print(len(list4))

for i in list1:

for j in range(len(list2)):

if i!=list2[j]:

continue

list5.append(i)

print(list5)

print(len(list5))

mohsen karimi · Answer 13 · ۱۴۰۰-۰۶-۲۶

mohsen karimi

2

۱۴۰۰-۰۶-۲۶ در ۱۷:۳۵

پاسخ دادن

سلام jahan

منظور استاد یکسان بودن مقدار و ایندکس پارامتر ها هست کد شما ۴ خروجی برای مثال بالا دارد ” Butter ” ایندکس یکسانی ندارد